Re: [xsl] Iteration of for() for first 100 intergers.

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Subject: Re: Iteration of for() for first 100 intergers.
From: Michael Kay <mike@xxxxxxxxxxxx>
Date: Thu, 18 Nov 2010 16:21:53 +0000

On 18/11/2010 16:09, ram wrote:

Hi,
    I am looking for simple for() which will iterate through first 100 numbers.   how can i do that.

for(int i=0;i<=100;i++){
    System.out.println("each value"+i);
}

In XPath 2.0:

for $i in 1 to 100 return .....

In XPath 1.0

you're out of luck. There's a workaround to iterate over a node-set containing n nodes, and use position().

Michael Kay
Saxonica

Current Thread
Iteration of for() for first 100 intergers. ram - 18 Nov 2010 16:09:41 -0000 Michael Kay - 18 Nov 2010 16:22:04 -0000 <= Hermann Stamm-Wilbrandt - 18 Nov 2010 20:42:31 -0000 Brandon Ibach - 18 Nov 2010 16:32:09 -0000

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