Re: [xsl] Full output all nodes depending on a conditional

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Subject: Re: Full output all nodes depending on a conditional
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Sun, 14 Nov 2010 18:21:06 +0100

Jimenez, Luis wrote:

   <xsl:template match="pd">
     <xsl:copy>
       <xsl:variable name="id" select="translate(detfac/pie/linea3,',','')"/>
      <xsl:if test="$id&gt; '500'">

Note that '>' and '<' with XSLT 1.0 work only on numbers so your '500' is converted the the number 500 anyway, meaning you could directly use <xsl:if test="$id > 500">

<xsl:apply-templates select="@* | picking"/>

I think you simply want to change the above to <xsl:apply-templates select="@* | node()"/> to ensure not only the "picking" child elements but others like the "detfac" are processed as well.

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/

Current Thread
Full output all nodes depending on a conditional Jimenez, Luis - 14 Nov 2010 16:35:55 -0000 Martin Honnen - 14 Nov 2010 17:21:27 -0000 <= Jimenez, Luis - 14 Nov 2010 18:46:14 -0000 Martin Honnen - 15 Nov 2010 09:32:02 -0000 Jimenez, Luis - 15 Nov 2010 23:40:00 -0000

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