Thanks Wendell.
I have to compare timings with Martin solution...
But this one is amazing :)

Best regards,
Fabien


-----Message d'origine-----
De : Wendell Piez [mailto:wapiez@xxxxxxxxxxxxxxxx]
Envoyi : mardi 23 novembre 2010 16:21
@ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re:  selecting nodes based on sibling values

Fabien,

At 09:45 AM 11/23/2010, you wrote:
>Let's say I have an XML like below...
>
><data>
>         <row>
>                 <level>40</level>
>                 <keycode>1254.45.12</keycode>
>         </row>
>         <row>
>                 <level>50</level>
>                 <keycode>1254.45.12.7</keycode>
>         </row>
>         <row>
>                 <level>50</level>
>                 <keycode>1254.45.12.8</keycode>
>         </row>
>         <row>
>                 <level>50</level>
>                 <keycode>1254.45.12.9</keycode>
>         </row>
>
>         <row>
>                 <level>40</level>
>                 <keycode>99.25.6</keycode>
>         </row>
>         <row>
>                 <level>50</level>
>                 <keycode>99.25.6.45</keycode>
>         </row>
>         <row>
>                 <level>50</level>
>                 <keycode>99.25.6.46</keycode>
>         </row>
></data>
>
>What could be the XPath expression to get the maximum number of nodes of
>level=50 in data those keycode starts like the level=40 line ?
>Here the answer would be 3 as the maximum number of level = 50 nodes for
>a given level = 40 is 3
>I have tried several things, but I am stuck....
>(I am using XSLT 2.0 on Saxon)

This is a bit tricky since associating the level 50 nodes with the
level 40 nodes is a bit tricky.

One way to do this is using a key (an old 1.0 upconversion trick):

<xsl:key name="get-level-50" match="row[level='50']"
   use="generate-id(preceding-sibling::row[level='40'][1])"/>

This enables you to get all the level 40 rows that belongs to any
level 50 row, using that row as context.

Then we can get a sequence representing the values of the counts like so:

//row[level='40']/count(key('get-level-50',generate-id(.))

and the max:

max(//row[level='40']/count(key('get-level-50',generate-id(.)))

Note: untested; watch out for typos.

Cheers,
Wendell



======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
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