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Evan Lenz
Lenz Consulting Group, Inc.
http://lenzconsulting.com
+1 (360) 297-0087

Hi Folks,

Consider this XML document:

<?xml version="1.0"?>
<N1:NumberList xmlns:N1="http://www.example1.org"
               xmlns:N2="http://www.example2.org">
        <Number>23</Number>
        <Number>41</Number>
        <Number xmlns:N3="http://www.example3.org">70</Number>
        <Number>103</Number>
        <Number>99</Number>
        <Number>6</Number>
</N1:NumberList>

Notice that there are three (3) namespaces, but two of them are unused:

http://www.example2.org
http://www.example3.org

I want an XSLT transform that will output all the unused namespaces in the input XML document.

Here's the solution I came up with:


<xsl:template match="*">
<xsl:variable name="elem" select="." />
<xsl:for-each select="namespace::*[. != 'http://www.w3.org/XML/1998/namespace']">
<xsl:variable name="ns" select="." />
<xsl:if test="not($elem/ancestor::*[namespace::* = $ns])">
<xsl:if test="not($elem/descendant-or-self::*[namespace-uri() = $ns])"> This namespace is unused: <xsl:value-of select="$ns" />
</xsl:if>
</xsl:if>
</xsl:for-each>
<xsl:apply-templates select="*" />
</xsl:template>


Is there a better solution? (I am using XSLT 1.0)

/Roger