Hi,

You could try this:

<xsl:template match="dir">
	<copy>
		<copy-of select="@*">
	</copy>
	<xsl:if test="following::dir[@name = current()/@name]">
		<xsl:apply-templates select="following::dir[@name = current()/@name]/*"/>
	</xsl:if>
</xsl:template>

Haven't tested this but the solution should be something like this.

cheers


Patrick Szabo
 XSLT-Entwickler

Tel.: +43 (1) 534 52 - 1573
Fax: +43 (1) 534 52 - 146

Patrick.Szabo@xxxxxxxxxxxxx

LexisNexis Verlag ARD Orac GmbH & Co KG
Marxergasse 25, 1030 Wien
FN 8333f, Handelsgericht Wien
http://www.lexisnexis.at/

-----UrsprC<ngliche Nachricht-----

Von: Mathieu Malaterre [mailto:mathieu.malaterre@xxxxxxxxx]
Gesendet: Donnerstag, 08. Juli 2010 11:30
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff:  Merging common XML tree

Hi there,

  I am trying to find a solution for the following problem. Let's
assume that my input XML tree looks like:

<dirs>
  <dir name="A">
    <dir name="B">
      <file name="C">
    </dir>
  </dir>
  <dir name="A">
    <dir name="B">
      <file name="D">
    </dir>
  </dir>
</dirs>

and my target output tree should looks like:

<dirs>
  <dir name="A">
    <dir name="B">
      <file name="C">
      <file name="D">
    </dir>
  </dir>
</dirs>

Basically I am trying to represent a dir/file structure in XML, where
I am not allowed to repeat common subdirectory. What XSL function
could I use to do that (XSTL 1.0 if possible).

Thanks !
--
Mathieu