Subject: Trying to understand XSLT processing
From: <ohaya@xxxxxxx>
Date: Mon, 14 Dec 2009 21:34:59 -0500
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Hi,
I have an XML file:
<SOAP:Envelope xmlns:saml="urn:oasis:names:tc:SAML:1.0:assertion" xmlns:samlp="urn:oasis:names:tc:SAML:1.0:protocol" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/" xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" xmlns:env="http://schemas.xmlsoap.org/soap/envelope/">
<SOAP:Header>
<wsse:Security SOAP:mustUnderstand="1">
</wsse:Security></SOAP:Header>
<SOAP:Body>
<m:hello xmlns:m="http://services">
<m:x>123</m:x>
</m:hello>
</SOAP:Body>
</SOAP:Envelope>
and I just want to output the <SOAP:Body> to a message, so I have an XSLT that looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope"
xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope">
<xsl:output method="xml" />
<xsl:template match="/">
<xsl:message>*****you just hit the XSLT ******</xsl:message>
<xsl:message>*****BODY CONTENTS****[<xsl:copy-of select="."/>]</xsl:message>
</xsl:template>
</xsl:stylesheet>
However, when I execute that XSLT, I'm getting an empty nodeset for the output:
*****you just hit the XSLT ******
*****BODY CONTENTS****[]
So, I was wondering if someone can explain what I am doing wrong with that XSLT above? Why doesn't the <xsl:copy-of> give me the <Body>?
Thanks, and sorry if this is probably a really dumb question :(...
Jim
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