Re: [xsl] sort a node across a dynamic group of files

Subject: Re: sort a node across a dynamic group of files
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Sun, 22 Nov 2009 20:51:32 +0100

J. Argyl Plath wrote:

Thank you for any help you can give on this matter. I appreciate any and all leads. I hope I haven't left any relevant information out.

Can't you generate a toc file listing the names of all entry files you want to process e.g.

<toc>
  <file>0001.xml</file>
  <file>0002.xml</file>
  <file>0003.xml</file>
</toc>

Then you could simply process e.g.

<xsl:template match="toc">
  <xsl:for-each select="document(file)/entry">
    <xsl:sort .../>
  </xsl:for-each>
</xsl:template>

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/

Current Thread
sort a node across a dynamic group of files J . Argyl Plath - 22 Nov 2009 19:28:37 -0000 Martin Honnen - 22 Nov 2009 19:52:15 -0000 <= J. Argyl Plath - 22 Nov 2009 19:57:56 -0000 G. Ken Holman - 22 Nov 2009 19:58:16 -0000 G. Ken Holman - 22 Nov 2009 20:06:45 -0000 J. Argyl Plath - 22 Nov 2009 20:29:05 -0000

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