Hi Martin

Thanks for the quick reply.  Both ULs and LIs need to be sorted by the
order attribute.  For example, the output I'm looking to achieve would
be:-

<ul>
	<li>item1</li>
	<ul>
		<li>item6</li>
		<ul>
			<li>
				<a href="#">item10</a>
			</li>
			<li>
				<a href="#">item8</a>
			</li>
			<li>
				<a href="#">item7</a>
			</li>
			<li>
				<a href="#">item9</a>
			</li>
		</ul>
		<li>item2</li>
		<ul>
			<li>
				<a href="#">item5</a>
			</li>
			<li>
				<a href="#">item4</a>
			</li>
			<li>
				<a href="#">item3</a>
			</li>
		</ul>
	</ul>
</ul>

I've tried your suggestion but it didn't seem to affect the order
unfortunately. :(

Thanks

Jim



On Tue, Oct 6, 2009 at 4:21 PM, Martin Honnen <Martin.Honnen@xxxxxx> wrote:
> jim mcgovern wrote:
>>
>> Hi All
>>
>> I'm trying to find the most efficient way of sorting a flat xml file
>> into a tree structure.  My xslt so far is pretty simple and sorts the
>> XML into a HMTL tree structure <ul><li><ul>...etc.  But what I'm
>> having trouble with is the most efficient way of sorting the content.
>> My tree structure needs to be ordered using the order attribute in the
>> xml.  My xml is:-
>>
>> <?xml version="1.0" encoding="utf-8" ?>
>>    <folders>
>>        <Item ID="1" ParentItem="" order="1" title="item1"/>
>>        <Item ID="2" ParentItem="1" order="2" title="item2"/>
>>        <Item ID="3" ParentItem="2" order="3" title="item3"/>
>>        <Item ID="4" ParentItem="2" order="2" title="item4"/>
>>        <Item ID="5" ParentItem="2" order="1" title="item5"/>
>>        <Item ID="6" ParentItem="1" order="1" title="item6"/>
>>        <Item ID="7" ParentItem="6" order="3" title="item7"/>
>>        <Item ID="8" ParentItem="6" order="2" title="item8"/>
>>        <Item ID="9" ParentItem="6" order="4" title="item9"/>
>>        <Item ID="10" ParentItem="6" order="1" title="item10"/>
>>    </folders>
>>
>> And my xslt so far is pretty simple:-
>>
>> <?xml version="1.0" encoding="UTF-8"?>
>> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>> version="1.0">
>>    <xsl:output indent="yes"/>
>>    <xsl:key name="val" match="Item" use="@ParentItem"/>
>> <xsl:template match="folders">
>>        <ul><xsl:apply-templates select="key('val', '')"/></ul>
>>    </xsl:template>
>>    <xsl:template match="Item">
>>        <xsl:choose>
>>            <xsl:when test="key('val', @ID)">
>>                <li><xsl:value-of select="@title"/></li>
>>                <ul><xsl:apply-templates select="key('val', @ID)"/></ul>
>>            </xsl:when>
>>            <xsl:otherwise>
>>                <li><xsl:value-of select="@title"/></li>
>>            </xsl:otherwise>
>>        </xsl:choose>
>>    </xsl:template>
>> </xsl:stylesheet>
>>
>> I'd appreciate any pointers on how to implement an efficient sort
>> using the order attribute!
>
> Do you want to sort the li children of each ul? Then the following change
to
> your stylesheet should do:
>
>    <xsl:template match="Item">
>        <xsl:choose>
>            <xsl:when test="key('val', @ID)">
>                <li><xsl:value-of select="@title"/></li>
>                <ul>
>                  <xsl:apply-templates select="key('val', @ID)">
>                    <xsl:sort select="order" data-type="number"/>
>                  </xsl:apply-templates>
>                </ul>
>            </xsl:when>
>            <xsl:otherwise>
>                <li><xsl:value-of select="@title"/></li>
>            </xsl:otherwise>
>        </xsl:choose>
>    </xsl:template>
>
>
>
> --
>
>        Martin Honnen
>        http://msmvps.com/blogs/martin_honnen/