Re: [xsl] Got xml base path in the xslt file

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Subject: Re: Got xml base path in the xslt file
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Tue, 15 Sep 2009 20:41:37 -0700

At 2009-09-16 10:29 +0800, Dongsheng Song wrote:

Hi all,
I use a xsl file to merge multiple xml files,  the master xml file like this:

<doc>
        <doc id="Intro" />
        <doc id="Configuration" />
        <doc id="Index" />
</doc>

The xsl file like this:

<xsl:for-each select="doc/doc">
    <xsl:variable name="fileName"><xsl:value-of select="@id"
/><xsl:text>.xml</xsl:text></xsl:variable>

    <xsl:for-each select="document($fileName)">
        <xsl:copy-of select="doc/div"/>
    </xsl:for-each>
</xsl:for-each>

Because the file path is relative of  the xsl file for 'document'
function,

This is only true because of the way you called the document() function. You are missing the second argument to use when the first argument is not a node.

I have to put xsl and xml files together.
Can I got the base path of master xml file, so I can store xsl and xml
file separately?

Supply a second argument which is the node from which to obtain the base URI:

document($fileName,.)

... will resolve a relative URI in $fileName against the base URI of the fragment from which the current node was obtained.

Then your XSL can be in any directory and the document() function will still be off of the data file fragment.

I hope this helps.

. . . . . . . . . . . . Ken

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Current Thread
Re: Got xml base path in the xslt file, (continued) Mukul Gandhi - 16 Sep 2009 03:16:22 -0000 Mukul Gandhi - 16 Sep 2009 08:43:15 -0000 Michael Kay - 16 Sep 2009 08:59:11 -0000 Mukul Gandhi - 16 Sep 2009 16:05:51 -0000 Message not available G. Ken Holman - 16 Sep 2009 03:42:47 -0000 <= Michael Kay - 16 Sep 2009 07:05:43 -0000 Andrew Welch - 16 Sep 2009 09:06:41 -0000

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