Subject: Re: How to replace a reference to a tag by the tag itself?
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 6 Aug 2009 13:49:35 +0100
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well doing a full job is complicated as the actual schema may be
skattered opver multiple xml files, but assuming that isn't thecase,
something like
<xsl:key name="g" match="xsd:group[@name]" use="@name"/>
then
<xsl:template match="xsd:group[@ref]">
<xsl:apply-templates select="key('g',@ref)/*"/>
</xsl:template>
together with an identity template to copy the rest of the stuff.
Of course xslt never handles tags, despite the subject line.
David
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