Hi Jeff,

Couldn't you use the XPATH count() function on the list of preceding
siblings to determine your position in the list?

>From /rows/row
<xsl:value-of select="count(preceding-sibling::*) + 1"/>
should print out the position in the list.

Regards,
Ben

Jeff Shelley wrote:
> Hello.
>    Does anybody know what xsl file can take this:
>
> <rows>
>    <row>
>        <name>John</name>
>        <otherName/>
>    </row>
>    <row>
>        <name>Paul</name>
>        <otherName/>
>    </row>
>    <row>
>        <name>Ringo</name>
>        <nickName>ClassCastException</nickName>
>    </row>
>    <row>
>        <name>George</name>
>        <otherName/>
>    </row>
> </rows>
>
>
> and turn it into this?
>
>     1-John
>     2-Paul
>     3-Ringo
>     4-ClassCastException
>     5-George
>
> Basically, I need the output number to keep incrementing and be
> continuous.  Everything I see about counters says "if you're
> implementing a counter you're doing it wrong", but I have absolutely
> no idea how to do this.
>
> I'd appreciate any help.  Thanks!
>

-- 

Ben Mendis
Support Specialist
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