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Selva Ganesh wrote:
How to convert without parent element, all the elements had in same level but I want the output is multi level elements, how is possible I did not understand where the 'no' elements for the 's2' elements get their contents from so the following only shows you how to group the elements with xsl:for-each-group group-starting-with: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:mf="http://example.com/2009/mf" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs mf" version="2.0"> <xsl:output method="xml" indent="yes"/> <xsl:template match="/*"> <reg> <xsl:for-each-group select="*" group-starting-with="h2[@class eq 'LegP1GroupTitle']"> <no> <xsl:value-of select="following-sibling::p[@class eq 'LegP1ParaText'][1]/span[@class eq 'LegP1No']"/> </no> <ti> <xsl:value-of select="."/> </ti> <xsl:for-each-group select="current-group() except ." group-starting-with="p[@class eq 'LegP1ParaText']"> <s1> <no>?</no> <pt> <xsl:value-of select="normalize-space(replace(., '\(\d+\)', ''))"/> </pt> </s1> <xsl:for-each-group select="current-group() except ." group-starting-with="p[@class eq 'LegP2ParaText']"> <s1> <no>?</no> <pt> <xsl:value-of select="replace(., '^\(\d+\)', '')"/> </pt> <xsl:sequence select="mf:group(current-group() except ., 3)"/> </s1> </xsl:for-each-group> </xsl:for-each-group> </xsl:for-each-group> </reg> </xsl:template> <xsl:function name="mf:group" as="element()*"> <xsl:param name="els" as="element()*"/> <xsl:param name="n" as="xs:integer"/> <xsl:for-each-group select="$els" group-starting-with="p[@class eq concat('LegP', $n, 'Container')]"> <xsl:element name="s{$n - 1}"> <no> <xsl:value-of select="span[@class eq concat('LegP', $n, 'No')]"/> </no> <pt> <xsl:value-of select="span[@class eq concat('LegP', $n, 'Text')]"/> </pt> <xsl:sequence select="mf:group(current-group() except ., $n + 1)"/> </xsl:element> </xsl:for-each-group> </xsl:function> </xsl:stylesheet> When applied to <?xml version="1.0" encoding="utf-8" ?> <root> <h2 class="LegP1GroupTitle">Determination that a </h2> <p class="LegP1ParaText"> <span class="LegP1No">3.</span>—(1) This regulation </p> <p class="LegP2ParaText">(2) Subject to paragraph (3)</p> <p class="LegP3Container"> <span class="LegP3No">(a)</span> <span class="LegP3Text">during an interview </span> </p> <p class="LegP3Container"> <span class="LegP3No">(b)</span> <span class="LegP3Text">the confession is in </span> </p> <p class="LegP3Container"> <span class="LegP3No">(c)</span> <span class="LegP3Text">the confession inclu</span> </p> <p class="LegP4Container"> <span class="LegP4No">(i)</span> <span class="LegP4Text">the period during </span> </p> <p class="LegP5Container"> <span class="LegP5No">(aa)</span> <span class="LegP5Text">the period during </span> </p> </root> the result with Saxon 9 is as follows: <?xml version="1.0" encoding="UTF-8"?>
<reg>
<no>3.</no>
<ti>Determination that a </ti>
<s1>
<no>?</no>
<pt>3. This regulation</pt>
</s1>
<s1>
<no>?</no>
<pt> Subject to paragraph (3)</pt>
<s2>
<no>(a)</no>
<pt>during an interview </pt>
</s2>
<s2>
<no>(b)</no>
<pt>the confession is in </pt>
</s2>
<s2>
<no>(c)</no>
<pt>the confession inclu</pt>
<s3>
<no>(i)</no>
<pt>the period during </pt>
<s4>
<no>(aa)</no>
<pt>the period during </pt>
</s4>
</s3>
</s2>
</s1>
</reg>-- Martin Honnen http://msmvps.com/blogs/martin_honnen/
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