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At 2009-04-24 18:04 +0200, Leo Studer wrote:
Note you could have just said the following without creating the variable, though I suppose some processors would optimize that out: <xsl:copy-of select="my:MakeTableRow(current-grouping-key(),current-group())"/> In the tag <xsl:for-each-group select="/results/match" group-by="team"> I would like to sort the outcome by the $tableRow/td[8] contents (i.e. the points) . How do I do that? In one pass you would need to recalculate the 8th column for each entry in the group. The approach Interesting ... with just a quick review, I suppose you are doing that recalculation since you are returning the row and indexing off of the 8th column, so I am unsure why the above does not work for you. Any suggestions? Create the rows and then sort them: <xsl:variable name="rows" as="element(tr)+">
<xsl:for-each-group select="/results/match" group-by="team">
<xsl:copy-of
select="my:MakeTableRow(current-grouping- key(),current-group())"/>
</xsl:for-each-group>
</xsl:variable>
<xsl:for-each select="$rows">
<xsl:sort select="td[8]"/>
<xsl:copy-of select="."/>
</xsl:for-each>That way you aren't doing the complicated row building twice, only once, and the second pass is a simple copy of nodes. I think you might find that better than trying to find out why rebuilding the row for the sort criteria isn't working for you. I hope this helps. . . . . . . . . . Ken p.s. just before hitting "send" I see David has quickly determined it was a namespace problem, so the above would be modified along the lines of: <xsl:variable name="rows" as="element(xhtml:tr)+">
<xsl:for-each-group select="/results/match" group-by="team">
<xsl:copy-of
select="my:MakeTableRow(current-grouping- key(),current-group())"/>
</xsl:for-each-group>
</xsl:variable>
<xsl:for-each select="$rows">
<xsl:sort select="xhtml:td[8]"/>
<xsl:copy-of select="."/>
</xsl:for-each>
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