Subject: RE: Fwd: using xquey in XSLT transformation
From: "Jim Earley" <xml.jim@xxxxxxxxx>
Date: Wed, 18 Mar 2009 17:52:12 -0600
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You can declare your own functions in XSLT 2.0:
<xsl:stylsheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:local="your-namespace"
version="2.0">
<xsl:function name="local:getPic">
<xsl:param name="node" as="node()"/>
<xsl:param name="searchValue" as="xs:string"/>
<xsl:choose>
<xsl:when test="empty($searchvalue)">
<xsl:sequence select="$node/pic-value"/>
</xsl:when>
<xsl:otherwise>
<xsl:sequence
select="local:ref($node//data-declaration[name=$searchvalue[1]], $searchValue[postion()
!= 1])"/>
</xsl:otherwise>
</xsl:choose>
</xsl:function>
<xsl:stylesheet>
Cheers,
Jim Earley
Senior XML Architect
Flatirons Solutions Corp.
The important thing is not to stop questioning. Curiosity has its own reason for
existing - Albert Einstein
-----Original Message-----
From: Michalmas [mailto:michalmas@xxxxxxxxx]
Sent: Wednesday, March 18, 2009 4:27 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Fwd: using xquey in XSLT transformation
Hello guys,
I have XQuery function. I need to use it in XSLT transformation. Is it possible?
d e c l a r e func t i on l o c a l : g e tPic ( $node as node ( ) ,
$ s ear chValue as x s : s t r i n g )
{
i f ( empty ($ searchValue ) ) then
$node/ pic-value
e l s e
l o c a l : r e f ($ node // de s c endant : :da ta-d e c l a r a t i o n
[ name=$s earchValue [ 1 ] ] [ 1 ] ,
$ searchValue [ p o s i t i o n ( ) != 1 ] )
};
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