> The template you wrote always returns the value for the child of the
> first <nameloc>. 

No, it returns the string value of (all) the nmlist child(ren) of the
nameloc which has the id specified in the linkend attribute of the
current HYPERTEXT.

> I need to interrogate each <nameloc> id value to find the one that
> matches @linkend for the current <HYPERTEXT>.  

That's what the code I posted did, using a key lookup.


On the xml you posted the template I showed produces this:

<?xml version="1.0" encoding="UTF-8"?><step><link item="item1"/></step>

which appears to be what you asked for (except that it is well formed)
your requested result had an unclosed link element.


<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates select="document/STEP"/>
</xsl:template>

<xsl:template match="STEP">
<step><xsl:apply-templates/></step>
</xsl:template>

<xsl:key name="id" match="nameloc" use="@id"/>
<xsl:template match="HYPERTEXT">
<link item="{key('id',@linkend)/nmlist}"/>
</xsl:template>

</xsl:stylesheet>


David

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