> match="p[count(node()) = 0] | q[count(node()) = 0]"
>
> or some other construct as you suggest. Though you could write this more
> tersely as
>
> match="p[not(node())] | q[not(node())]"

Sometimes it's bit nicer to keep them separate:

match="p[not(node())]"/>
match="q[not(node())]"/>

...so when you're scanning through the list of templates in your IDE
it's easier to spot.



-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/