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Jean-Philippe Martin wrote:
I'm trying to sort a <xsl:variable> containing 22 nodes and store this sorted list into another xsl:variable. Is there a way to do this ? There is a way if you show us your XML input and how exactly you initialize your first variable. Assuming the XML input document is <root> <foo>10</foo> <foo>2</foo> <foo>1</foo> <foo>4</foo> </root> then this stylesheet <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes"/> <xsl:template match="/">
<xsl:variable name="v1" select="root/foo"/>
<xsl:variable name="v2">
<xsl:for-each select="$v1">
<xsl:sort select="." data-type="number"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
<result>
<xsl:copy-of select="$v2"/>
</result>
</xsl:template></xsl:stylesheet> outputs <result> <foo>1</foo> <foo>2</foo> <foo>4</foo> <foo>10</foo> </result> Variable v1 has the foo elements from the XML input, variable v2 a result tree fragment of the sorted foo elements. -- Martin Honnen http://JavaScript.FAQTs.com/
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