It's always useful, rather than saying "it doesn't work", to say exactly how
it fails. Error message? Wrong results?

I can't see anything wrong with your code, it looks perfectly legal to me -
but I'm trying to debug it without the benefit of seeing its output.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Joe Barwell [mailto:jbar@xxxxxxxx] 
> Sent: 10 October 2008 11:21
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Parameters into variables
> 
> Hello,
> 
> XSLT 1.0 (e.g. Firefox 3.0, etc.)
> 
> I have a template as follows:
> 
> <xsl:template name="getCurrencySymbol">
> 	<xsl:param name="aCurrency" />
> 	<xsl:choose>
> 		<xsl:when test="$aCurrency='AUD'">A$</xsl:when>
> 		<xsl:when test="$aCurrency='EUR'">&#x20AC;</xsl:when>
> 		<xsl:when test="$aCurrency='GBP'">&#163;</xsl:when>
> 		<xsl:when test="$aCurrency='NZD'">NZ$</xsl:when>
> 		<xsl:when test="$aCurrency='USD'">US$</xsl:when>
> 		<xsl:otherwise></xsl:otherwise>
> 	</xsl:choose>
> </xsl:template>
> 
> 
> At the top of my xsl stylesheet I want to put its value into a global
> variable:
> 
> <xsl:variable name="theCurrencySymbol">
> 	<xsl:call-template name="getCurrencySymbol">
> 		<with-param name="aCurrency" select="'NZD'" />
> 	</xsl:call-template>
> </xsl:variable>
> 
> But this does not work. Mangano (2003, p.120) shows that it 
> will work if the template is called _without_ a parameter, 
> and indeed I am able to do so successfully if I use a global 
> variable, e.g. $baseCurrency, and change my getCurrencySymbol 
> template so that it uses $baseCurrency (i.e. 
> ignoring the $aCurrency parameter).
> 
> The problem is that I would like to be able to re-use my 
> getCurrencySymbol template elsewhere, but with a specified 
> parameter in its call rather than a global.
> 
> Is it really not possible to put the result of a template 
> into a variable, if that template is being called using a 
> parameter? I cannot think why such a minor distinction would 
> be in the language.
> 
> Cheers!
> 
> Joe