Subject: Re: my node position within a certain context, efficiently?
From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>
Date: Sun, 26 Oct 2008 09:51:05 +0530
|
On Sun, Oct 26, 2008 at 12:37 AM, Syd Bauman <Syd_Bauman@xxxxxxxxx> wrote:
> This results in all of the <thing> elements being counted
> irrespective of their position within a <box>, though, whereas I had
> asked to count their positions with respect to their ancestor <box>.
Here's another approach ...
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output method="xml" indent="yes" />
<xsl:template match="/">
<result>
<xsl:apply-templates select="//box//thing"/>
</result>
</xsl:template>
<xsl:template match="box//thing">
<thing myCount="{count(ancestor::box[1]//thing[. << current()]) + 1}">
<xsl:value-of select="."/>
</thing>
</xsl:template>
</xsl:stylesheet>
Here I have used the XPath 2.0 node comparison operator <<.
--
Regards,
Mukul Gandhi
|