There are no built-in functions for parsing dates in non-standard formats
(as distinct from formatting them), but you can do it easily enough using
regular expressions and xsl:analyze-string.

The precise solution depends on a precise definition of your input format,
which you haven't given us.

Michael Kay
http://www.saxonica.com/
 

> -----Original Message-----
> From: Pankaj Chaturvedi [mailto:pankaj.chaturvedi@xxxxxxxxx] 
> Sent: 16 September 2008 09:49
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Date YYYYMMDD format XSLT 2.0
> 
> 
> Hi,
> 
> I have an element which has the date in the below format in 
> an attribute:
> 
> Input
> ================
> <chapter version="Feb. 2000"/>
> 
> The date could be optional can be taken as 01 by default. So 
> the desired output required in "YYYYMMDD format".
> 
> Output Required
> ================
> <chapter version="20000201"/>
> 
> 
> I've been going thru the Michael Kay's book and found it has 
> an example which does the trick vice versa. I mean YYYYMMDD 
> to 01 Feb 2000 for instance. 
> 
> I am using the  XSLT 2.0 and thinking of using translate() 
> functions (for
> months) to get this done. Is there any better way to achieve 
> this? Any suggestions will be highly appreciated. 
> 
> Best,
> 
> Pankaj Chaturvedi
> 
> ==============================================================
> ==============
> ================
> 
> 
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