Re: [xsl] Finding and comparing a parent attribute for the n

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Subject: Re: Finding and comparing a parent attribute for the next result in a for-each loop
From: Kate Busch Petersen <kate.busch-petersen@xxxxxxxxxxxxx>
Date: Fri, 08 Aug 2008 09:00:34 +0100

At 06:10 08/08/2008, you wrote:

Can you post the HTML you want to create from that fragment above?

--
        Martin Honnen
        http://JavaScript.FAQTs.com/
------------------------------

Date: Thu, 7 Aug 2008 17:41:28 +0100 To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> From: "Michael Kay" <mike@xxxxxxxxxxxx> Subject: RE: Finding and comparing a parent attribute for the next result in a for-each loop Message-ID: <213750C294654BE1BBFBB903B53D7EDF@Sealion>
It looks to me as if this is more of a grouping problem than a sorting
problem.
If you are really stuck with XSLT 1.0 then you need to learn about Muenchian
grouping (http://www.jenitennison.com/xslt/grouping).
Michael Kay
http://www.saxonica.com/

The HTML I want to produce for this part is a simple list of all the years:

<li> <a href="index.asp?pageid=60&section=articles&subsection=section1&thisyear=2008">2008</a> </li> <li> <a href="index.asp?pageid=60&section=articles&subsection=section1&thisyear=2007">2007</a> </li>

And so on....

I've built the first two levels of navigation (sorting by section and displaying subsections), the html for that looks like:

<h2 class="title">Section selected</h2> <ul class="tabs"> <li> <a href="index.asp?pageid=60&section=articles" >All</a> </li> <li> <a href="index.asp?pageid=60&section=articles&subsection=section1">Section 1</a> </li> </ul> <ul class="tabs_sub"> <li> <a href="index.asp?pageid=60&section=articles&subsection=section1">Latest</a> </li> </ul>

Now I need to pop the years after the "latest" tab.

I have had a look at Muenchian grouping, but my problem is grabbing and sorting (or grouping) by the attribute from the parent element. I'll have another look though.

Kate Busch-Petersen

Current Thread
Finding and comparing a parent attribute for the next result in a for-each loop Kate Busch Petersen - 7 Aug 2008 16:28:30 -0000 Martin Honnen - 7 Aug 2008 16:37:32 -0000 Michael Kay - 7 Aug 2008 16:41:48 -0000 <Possible follow-ups> Kate Busch Petersen - 8 Aug 2008 08:01:00 -0000 <=

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