Thanks, Colin,


Although the requirements cannot assume how many levels there are between the
root node and the desired node, your solution points me to something like
this. Does this work?


//[name() == "a" and name() == "c"]




--- On Fri, 8/29/08, Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> wrote:

> From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx>
> Subject: Re:  (simple?) xpath question
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Date: Friday, August 29, 2008, 12:22 PM
> >>>>> "Mark" == mark bordelon
> <markcbordelon@xxxxxxxxx> writes:
>
>     Mark> All *help*!    What is the best way to query
> xml with xpath
>     Mark> to get a disjoint nodelist? Specifically i
> want to include
>     Mark> just the root node alongwith a descendent
> node.    XML:  
>     Mark> <a>   <b>     <c>    
> </c>  </b> </a>   XPATH:   //c  
>     Mark> DESIRED RESULT NODELIST: i.e. not this:
> <c> </c>   but
>     Mark> rather this: <a>   <c>  
> </c> </a>
>
> One possibility is:
>
> //*[name() != "b"]
>
> It depends on your exact requirements.
> --
> Colin Adams
> Preston Lancashire