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This is a bit clunky but assuming your source data is in source.xml
<?xml version="1.0"?> <doc> <graphic picfile="I970106058X_bulb"/> <graphic picfile="I970106058X_dummy"/> </doc> and your filelist is in filelist.xml <?xml version="1.0"?> <files> <file>./970106058X_c01_0002.tif</file> <file>./970106058X_c01_0001.tif</file> <file>./970106058X_bulb.tif</file> <file>./970106058X_0000.tif</file> <file>./970106058X_c01_0003.tif</file> </files> Then this seems to work. <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes"/> <xsl:variable name="files" select="document('filelist.xml')"/> <xsl:template match="/">
<doc>
<xsl:apply-templates/>
</doc>
</xsl:template><xsl:template match="graphic"> <xsl:variable name="file" select="substring-after(concat(@picfile,'.tif'),'I')"/> <node picfile="{@picfile}">
<xsl:attribute name="matched">
<xsl:choose>
<xsl:when test="$files/files/file[contains(.,$file)]">
<xsl:value-of select="true()"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="false()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
</node>
</xsl:template>
</xsl:stylesheet>peter@radish:~/xxx$ xsltproc process.xsl source.xml <?xml version="1.0"?> <doc> <node picfile="I970106058X_bulb" matched="true"/> <node picfile="I970106058X_dummy" matched="false"/> </doc> peter@radish:~/xxx$ The $files/files/file[contains(.,$file)] does not seem to want to be converted into a boolean and I couldn't construct a way of getting it to match. There has got to be a better way!
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