Subject: Re: position and loop problem
From: henry human <henry_human@xxxxxxxx>
Date: Thu, 14 Aug 2008 15:23:54 +0200 (CEST)
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Tahnks
> What do you wanna do exactly?
what i am going to do is, to get the number of the
"section" elements from the XML file, than make a loop
which turns for so many time as the number of the
"section" element existed in the XML file!
I hope i was clear now .
--- Florent Georges <lists@xxxxxxxxxxxx> schrieb:
> henry human wrote:
>
> Hi
>
> > I save the number of a specific node as follow and
> get
> > the right number for the node which is 2:
> > <xsl:variable name="var"
> >
>
select="count(document/elements/element[@type='section'])"/>
> > However when I try it in a for-each loop as follow
> I
> > get 6 times looping!
> > Hier is the for-each loop:
>
> > <xsl:for-each select="//*[position() <= $var]">
>
> position() doesn't behave as you seem to think it
> does. What you get
> means there are in the input tree 6 elements that
> are the first or
> second child of their parent element.
>
> What do you wanna do exactly?
>
> Regards,
>
> --drkm
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