Subject: Re: How to produce X when an attribute of an element does not exist or equals Y?
From: Mark Carlson <carlsonm@xxxxxxxxxxxxxxxx>
Date: Tue, 8 Jul 2008 20:05:13 -0700 (PDT)
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Use this test in your xsl:if:
data-field[@tag='555'][@ind1='8' or not(@ind1)]
On Tue, 8 Jul 2008, Joyce Celeste Chapman wrote:
Hi, I'm new to the listserv and to XSL. Using the XML below and XSLT 1.0, I
would like content to appear both when an attribute of an element does not
exist and when it equals X. Specifically, I would like the contents of
data-field tag 555 to appear if this data-field does not have any "ind1"
attribute, or if its ind1 equals 8.
Data fields with indicators versus no indicators in my XML look like this:
<data-field tag="555" ind1="0">
<subfield code="a">...</subfield>
</data-field>
<data-field tag="555">
<subfield code="a">...</subfield>
</data-field>
This is the XSLT I have figured out, minus the missing part:
<xsl:if test="data-field[@tag='555'][@ind1='8'] | ...or if a data-field with
attribute 555 has no attribute ind1">
<otherfindaid encodinganalog="555">
<xsl:for-each select="data-field[@tag='555'][@ind1='8'] | ...or if a
data-field with attribute 555 has no attribute ind1">
<p>
<xsl:value-of select="."/>
</p>
</xsl:for-each>
</otherfindaid>
</xsl:if>
I would be very grateful for any help. Thank you!
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