[xsl] xsl:sort with XSLT 2.0 translated to XSLT 1.0

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Subject: xsl:sort with XSLT 2.0 translated to XSLT 1.0
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Thu, 19 Jun 2008 15:26:47 +0200

Assuming 'foo' elements can have a 'bar' and a 'baz' attribute and you want to process them sorted on @bar if present, otherwise on @baz then the following XSLT 2.0

<xsl:apply-templates select="foo">
  <xsl:sort select="(@bar, @baz)[1]"/>
</xsl:apply-templates>

does that nicely I think.

How would you translate that to XSLT 1.0? I can only think of a temporary tree (created with a node-set extension function) where you create a new attribute merging the two attributes first, then process the temporary tree sorted on the new attribute.

--

	Martin Honnen
	http://JavaScript.FAQTs.com/

Current Thread
xsl:sort with XSLT 2.0 translated to XSLT 1.0 Martin Honnen - 19 Jun 2008 13:27:16 -0000 <= Andrew Welch - 19 Jun 2008 13:31:18 -0000 Martin Honnen - 19 Jun 2008 13:35:29 -0000 David Carlisle - 19 Jun 2008 13:37:59 -0000 Andrew Welch - 19 Jun 2008 13:45:14 -0000

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