Subject: Re: XSL/XPath to generate a list of ancestors?
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Mon, 12 May 2008 19:15:26 +0200
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Nathan Potter wrote:
On May 12, 2008, at 10:05 AM, Martin Honnen wrote:
Nathan Potter wrote:
I tried this:
<xsl:template match="*" name="fullNameWorker" mode="fullName">
<xsl:if test="generate-id(.)!=generate-id(/)">
You have a template for element nodes (match="*") so why do you test
generate-id(.) != generate-id(/)
? An element (.) is never a root node (/).
Because the template recursively ascends the document I need to test
that I have arrived at the top.
But your template with match="*" is never processed for the root node
which is match="/". If anything makes sense then
generate-id(.) != generate-id(/*)
as that compares the matched element to the root element (which is
different from the root node).
--
Martin Honnen
http://JavaScript.FAQTs.com/
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