Excellent! Thank you very much for your help. 

--- Martin Honnen <Martin.Honnen@xxxxxx> wrote:

> sudheshna iyer wrote:
> > I am using xsl:stylesheet version="1.0".
> 
> Here is an XSLT 1.0 stylesheet that produces the
> result you described. 
> You only need to complete the "translation table"
> for the months:
> 
> <xsl:stylesheet
>    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>    xmlns:dt="http://example.com/2008/data"
>    version="1.0">
> 
>    <xsl:output method="text"/>
> 
>    <data xmlns="http://example.com/2008/data">
>      <month s="Jan" n="01"/>
>      <month s="Feb" n="02"/>
>      <month s="Mar" n="03"/>
>      <month s="Apr" n="04"/>
>      <!-- add other months here -->
>    </data>
> 
>    <xsl:template match="/">
>      <xsl:apply-templates select="rss/channel/item">
>        <xsl:sort data-type="number"
> order="descending"
>          select="concat(substring(SortDate, 13, 4), 
> document('')/xsl:stylesheet/dt:data/dt:month[@s = 
> substring(current()/SortDate, 9, 3)]/@n,
> substring(SortDate, 6, 2))"/>
>      </xsl:apply-templates>
>    </xsl:template>
> 
>    <xsl:template match="item">
>      <xsl:value-of
> select="concat(substring(SortDate, 13, 4), '-', 
> document('')/xsl:stylesheet/dt:data/dt:month[@s = 
> substring(current()/SortDate, 9, 3)]/@n, '-',
> substring(SortDate, 6, 2), 
> '
', title, '

')"/>
>    </xsl:template>
> 
> </xsl:stylesheet>
> 
> 
> -- 
> 
> 	Martin Honnen
> 	http://JavaScript.FAQTs.com/