Re: [xsl] Cannot process a result tree fragment as a node-se

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Subject: Re: Cannot process a result tree fragment as a node-set under XSLT 1.0 - My alternative don´t function
From: "Alejandro" <alexcontini@xxxxxxxx>
Date: Sat, 12 Apr 2008 18:50:14 +0100

Hi Michael,

Thank you so much for the quick response.

Michael >>However, it's not clear to me that you need to create an RTF in the first place. Why not define $filter as <xsl:variable name="filter" select="//RecursoEx1[($option=1 and F_FIN=$date1 and contains(TITULO,'o')) or ($option=2 and F_FIN=$date2)]"/>

I want to count the RecursoEx1 elements: <p>Number: <xsl:value-of select="count(exsl:node-set($filter)/RecursoEx1)"/></p> CORRECT!

I want to iterate over the RecursoEx1 elements:
   <xsl:for-each select="exsl:node-set($filter)/RecursoEx1"> CORRECT !

I use xsl:copy-of and exsl:node-set because to error "Cannot process a result tree fragment as a node-set under XSLT 1.0" if i code :

<xsl:variable name="filtro">
       <xsl:choose>
           <xsl:when test="$option=1">
               <xsl:copy-of
select="//RecursoEx1[F_FIN=$date1]"/></xsl:when>
           <xsl:otherwise>
               <xsl:copy-of
select="//RecursoEx1[F_FIN=$date2]"/></xsl:otherwise>
       </xsl:choose>
   </xsl:variable>

<p>Number: <xsl:value-of select="$filter"/></p>

   <xsl:for-each select="$filter">
        <p><xsl:value-of select="TITULO"/></p>
   </xsl:for-each>

and i don4t know if exits another posibility. Exists??

The variable "option" is to received from one formulary, but there are more and then the "filter" will be dynamic.

How can i do to construct the filter dynamic? For example, i receive one varible named "title" from the formulary with the value: "John Martin Car Monday" and i like to enumerate the RecursoEx1 elements that meet with this condition: TITLE=John or TITLE=Martin or TITLE=Car or TITLE=Monday.

or title variable is Apple Pencil, ..... then the condition will be TITLE=Apple or TITLE=Pencil

i don4t know how may parameters i will receive in advance..

Thanks again Michael,

Alexander

----- Mensaje original ----- De: "Michael Kay" <mike@xxxxxxxxxxxx> Para: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Enviado: sabado, 12 de abril de 2008 14:03 Asunto: RE: Cannot process a result tree fragment as a node-set under XSLT 1.0 - My alternative don4t function


The node-set returned by the exsl:node-set() function will always contain a
single (document or root) node. Perhaps you wanted its children:
exsl:node-set()/*.

However, it's not clear to me that you need to create an RTF in the first
place. Why not define $filter as

<xsl:variable name="filter"
  select="//RecursoEx1[($option=1 and F_FIN=$date1 and
contains(TITULO,'o'))
                       or ($option=2 and F_FIN=$date2)]"/>

Note also, that horrible bit of disable-output-escaping can be avoided by
setting the doctype-system and doctype-public attributes on xsl:output.

Michael Kay
http://www.saxonica.com/

-----Original Message-----
From: Alejandro [mailto:alexcontini@xxxxxxxx]
Sent: 12 April 2008 13:05
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Cannot process a result tree fragment as a
node-set under XSLT 1.0 - My alternative don4t function

Hello, i want to recover any records in function of one
variable (option in this case), and i don4t know to do it. I
want to print the TITULO element the those records.
Can you help me, please?

Cheers,
Alexander


********************************* XML
*************************************

<?xml version="1.0"?>

<List>
<RecursoEx1>
<TITULO>Sara Baras</TITULO>
<F_INICIO>20080125000000</F_INICIO>
<F_FIN>20080211000000</F_FIN>
</RecursoEx1>

<RecursoEx1>
<TITULO>Exposicion de pintura</TITULO>
<F_INICIO>20080201000000</F_INICIO>
<F_FIN>20080211000000</F_FIN>
</RecursoEx1>

<RecursoEx1>
<TITULO>Inaguracion de ...</TITULO>
<F_INICIO>20080205000000</F_INICIO>
<F_FIN></F_FIN>
</RecursoEx1>

<RecursoEx1>
<TITULO>Clausura de ..</TITULO>
<F_INICIO>20080101000000</F_INICIO>
<F_FIN>20080205000000</F_FIN>
</RecursoEx1>

</List>

********************** XSL **********************

<?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet
xmlns:i18n="http://apache.org/cocoon/i18n/2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:exsl="http://exslt.org/common"
    extension-element-prefixes="exsl" version="1.0">

<xsl:output method="html" media-type="text/html;charset=iso-8859-1"
indent="yes" encoding="ISO-8859-1" omit-xml-declaration="yes" />

<xsl:variable name="date1" select="20080205000000"></xsl:variable>
<xsl:variable name="date2" select="20080211000000"></xsl:variable>
<xsl:variable name="option" select="1"></xsl:variable>

<xsl:template match="/">

<xsl:text disable-output-escaping="yes"><![CDATA[<!DOCTYPE
html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">]]></xsl:text>

<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="es">

<head>
 <title>Gabinete of Prensa</title>
    <meta http-equiv="Content-Type" content="text/html;
charset=iso-8859-1"
/>
</head>

<body>

    <xsl:variable name="filter">
        <xsl:choose>
            <xsl:when test="$option=1">
                <xsl:copy-of
select="//RecursoEx1[F_FIN=$date1 and
contains(TITULO,'o')]"/></xsl:when>
            <xsl:otherwise>
                <xsl:copy-of
select="//RecursoEx1[F_FIN=$date2]"/></xsl:otherwise>
        </xsl:choose>
    </xsl:variable>

 <p>Number: <xsl:value-of
select="count(exsl:node-set($filter))"/></p> <!-- DON'T FUNCTION -->

 <xsl:for-each select="exsl:node-set($filter)">
     <p><xsl:value-of
select="exsl:node-set($filter)/TITULO"/></p>      <!--
DON'T FUNCTION -->
</xsl:for-each>

</body>
</html>
</xsl:template>

</xsl:stylesheet>

Current Thread
Cannot process a result tree fragment as a node-set under XSLT 1.0 - My alternative don´t function Alejandro - 12 Apr 2008 12:07:56 -0000 Martin Honnen - 12 Apr 2008 12:33:21 -0000 Alejandro - 12 Apr 2008 13:30:18 -0000 Michael Kay - 12 Apr 2008 13:04:02 -0000 Alejandro - 12 Apr 2008 17:53:09 -0000 <= Michael Kay - 12 Apr 2008 19:04:01 -0000

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