Subject: Re: An (almost) identity stylesheet
From: "bryan rasmussen" <rasmussen.bryan@xxxxxxxxx>
Date: Thu, 10 Apr 2008 10:49:40 +0200
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oops put in the @ in attrib2, make is xsl:attribute name= attrib2
On Thu, Apr 10, 2008 at 10:46 AM, bryan rasmussen
<rasmussen.bryan@xxxxxxxxx> wrote:
> think it should be like this you're looking for.
>
>
> <xsl:template match="*">
> <xsl:copy><xsl:apply-templates select="@*"/><xsl:apply-templates/></xsl:copy>
> </xsl:template>
> <xsl:template match="@*">
> <xsl:copy/>
> </xsl:template>
> <xsl:template match="@attrib2">
> <xsl:attribute name="@attrib2">0</xsl:attribute>
> </xsl:template>
>
> cheers,
> Bryan Rasmussen
>
>
> On Thu, Apr 10, 2008 at 10:40 AM, Karol Krenski <mimooh@xxxxxxxxxxxxxxx> wrote:
> > Hi list,
> >
> > I am a novice to XSLT, learned mainly form online tutorials. This XSLT
> > thing is killing me. Can't figure out how to transform my doc.xml:
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> > <foo>
> > <bar>
> > <date attrib1='aaaaaaa' attrib2='bbbbbb'>25-02-08</date>
> > ^
> > <name attrib3='null'>AAAAAAAAAAAAAAA</name>
> > </bar>
> > <bar>
> > <date attrib1='cccccc' attrib2='dddddd'>26-02-08</date>
> > ^
> > <name attrib4='null'>BBBBBBBBBBBBBBB</name>
> > </bar>
> > </foo>
> >
> >
> > into
> >
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> > <foo>
> > <bar>
> > <date attrib1='aaaaaaa' attrib2='0'>25-02-08</date>
> > ^
> > <name attrib3='null'>AAAAAAAAAAAAAAA</name>
> > </bar>
> > <bar>
> > <date attrib1='cccccc' attrib2='0'>26-02-08</date>
> > ^
> > <name attrib4='null'>BBBBBBBBBBBBBBB</name>
> > </bar>
> > </foo>
> >
> > Can somebody please suggest the correct stylesheet?
> >
> > I am blindly typing mainly 'copy' or 'copy-of' in my templates and the
> > output generation mechanics make little sense to me. The docs, comparing
> > to other programing documentation seems hard to understand. Could
> > somebody suggest good docs, please?
> >
> > Regards,
> > Karol
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