Subject: RE: Easy question, big headache.
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Tue, 11 Mar 2008 08:33:24 -0000
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> And I need to output some of these records, but not all of
> them. The rules upon which I decide to output are complex,
> and I won't bore you with the details.
Unfortunately it all depends on the detail.
If you can express the rules in an XPath expression EXP, then you can do:
<xsl:for-each select="record[EXP]">
<xsl:copy-of select="."/>
<xsl:if test="position() mod 5 = 0">
<marker/>
</xsl:if>
</xsl:for-each>
In XSLT 2.0 this always works - because EXP can call a stylesheet function
that can do any computation you like. In 1.0 it rather depends on EXP.
>
> In any other language, it's easy easy:
>
Writing in a language you know is always easier than in one that's new!
Michael Kay
http://www.saxonica.com/
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