Subject: Re: use of $foo/(//path)
From: David Carlisle <davidc@xxxxxxxxx>
Date: Mon, 4 Feb 2008 17:54:56 GMT
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> Maybe using a different example
// expands to different things
$actor/(//bar)
is
$actor/(fn:root(self::node()) treat asdocument-node()/descendant-or-self::node()/bar)
$actor//bar
is
$actor/descendant-or-self::node()/bar
maybe it's clearer with / rather than //
$actor/(/)
is
$actor/root(.)
(more or less)
$actor//
is a syntax error.
David
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