Now I have another problem. In the stylesheet article will be one param like this:

<xsl:param name="class">article</xsl:param>

Instead of use 'article' like in your solutions, I need to use $class

<xsl:template match="xs:element[@name=$class]/xs:complexType/xs:all">

but occurs an error and I don't know how correct it

	Martin Honnen
	http://JavaScript.FAQTs.com/