Subject: RE: xpath query
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Sat, 19 Jan 2008 00:46:08 -0000
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In XSLT 2.0, when you do <xsl:value-of select="EXPR"/> and EXPR selects a
sequence of nodes, the output consists of the string-values of those nodes,
separated by a single space.
If you want to copy the nodes to the output rather than extracting their
string values, try <xsl:copy-of>.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: Sean Tiley [mailto:sean.tiley@xxxxxxxxx]
> Sent: 18 January 2008 23:46
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: xpath query
>
> Hi there,
> I am still struggling with mostof this stuff, but I have a
> question related to the original data.
>
> <ROOT>
> <LEVEL2>
> <B>
> <a>100</a>
> <b apply="1">100</b>
> <c>100</c>
> </B>
> <C>
> <a>100</a>
> <b>100</b>
> <c apply="1">100</c>
> </C>
> </LEVEL2>
> </ROOT>
>
> If I create the following stylesheet I get 100 100 output
>
> <xsl:stylesheet
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
> <xsl:template match="ROOT">
> <html>
> <xsl:value-of select="LEVEL2/*/*[@apply='1']"/>
> </html>
> </xsl:template>
> </xsl:stylesheet>
>
> What I am not clear on is why does this return values and not nodes?
> Or is this really returning both nodes and I am getting the
> value of each one because of the <xsl:value-of select="..."/>
> expression?
>
> As far as I can figure the expression ROOT/LEVEL2/*/*[@apply='1']"
> says give me the nodes that have the arrtibute apply=1 and
> are grandchildren of level2.
>
> I kind of though to get both values I would have to do something like
>
> <xsl:template match="ROOT">
> <xsl:for-each select="LEVEL2/*/*[@apply='1']">
> <xsl:value-of select="."/>
> </xsl:for-each>
> </xsl:template>
>
> Sorry if this seems really trivial but it helps me to better
> understand.
>
> --
> Thanks
> Sean
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