Hi there,
I am new to xslt but I have an xml file in the following format
<root>
   <file name=3D"c:\blah\blah\class.java">
       <error line=3D"1" message=3D"Parameter status should be final"/>
   </file>
</root>

I would like to be able to replace the name attribute of the file =
element in the original file and leave the rest of the file intact, then =
pass the results to a different stylesheet.

I had a look at the replace function and tried something like this
<xsl:value-of select=3D'replace(@name,"c:\blah\blah\*","files")'/>

Any advice or suggestions are welcomed, perhaps another function should =
be used but replace sure seems right

Thanks
Sean