Subject: Re: normalize-space processing all nodes hack?
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Thu, 01 Nov 2007 17:22:53 +0100
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From what you are writing I understand you are using XSLT 1.0, because
in XSLT 2.0 your expression would give an error.
The way to do this is simply:
select = "normalize-space(A)"
which will give you the text content of node A (and thus of all its
children).
HTH,
Cheers,
-- Abel Braaksma
Kolacm Toma9 wrote:
Hi!
I'd like to fill variable textOnly by normalized string of all text of the element A. I'm just wondering is there any way, I could write it as one XPath expression, like:
<xsl:variable name="textOnly" select="normalize-space(A//text())"/>
(but here only the first text node is used)?
Please note, I'm interested only in the "one XPath expression" way, I know how solve problem in different way*.
Thanks, Tomas
*like:
<xsl:variable name="textOnlyPre">
<xsl:copy-of select="A//text()">
</xsl:variable>
<xsl:variable name="textOnly" select="normalize-space($textOnlyPre)"/>
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Abel Braaksma - 1 Nov 2007 16:26:28 -0000 <=
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