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At 2007-11-03 12:05 -0700, Avaneesh Ramprasad wrote:
I have a requirement to write a xsl transformation to find the node which has the maximum number of elements Not sure where you are having the problem, but XSLT 2 provides the max() function that makes this very easy. I hope the solution below helps. You can optimize the speed by putting the max value into a variable and testing against that, but I just wrote the XPath as I said the requirement aloud, so this is what I ended up with. . . . . . . Ken T:\ftemp>type avaneesh.xml
<Sample>
<Toyota>
<Car>Camry</Car>
<Car>Corrola</Car>
</Toyota>
<Honda>
<Car>Accord></Car>
<Car>Civic</Car>
<Car>Pilot</Car>
</Honda>
<Mitsubishi>
<Car>Lancer</Car>
<Car>Lancer</Car>
<Car>Lancer</Car>
</Mitsubishi>
<Hyundai>
<Car>Sonata</Car>
<Car>Accent</Car>
</Hyundai>
</Sample>T:\ftemp>type avaneesh.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xsd"
version="2.0"><xsl:output method="text"/> <xsl:template match="/">
<xsl:for-each select="/Sample/*[count(Car)=max(/Sample/*/count(Car))]">
<xsl:value-of select="name(.)"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template></xsl:stylesheet> T:\ftemp>xslt2 avaneesh.xml avaneesh.xsl con Honda Mitsubishi T:\ftemp> -- Comprehensive in-depth XSLT2/XSL-FO1.1 classes: Austin TX,Jan-2008 World-wide corporate, govt. & user group XML, XSL and UBL training RSS feeds: publicly-available developer resources and training G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995) Male Cancer Awareness Nov'07 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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