In XSLT 1.0 the answer is no. The usual remedy is to pass it in to the
transformation as a parameter.

Michael Kay
http://www.saxonica.com/
 

> -----Original Message-----
> From: Vankadaru.Gupta@xxxxxxxxxxxxxxxxxx 
> [mailto:Vankadaru.Gupta@xxxxxxxxxxxxxxxxxx] 
> Sent: 16 October 2007 13:44
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  how to get xml file name in xsl
> 
> Hi, 
> 
> Is it possible in XSL to get the file name of the XML 
> document it is currently processing?
> 
> I am using MSXML and the tag "document-uri(/)" does not work for me.
> 
> Can anybody please help me out?
> 
>  
> 
> Thanks
> 
> Nagesh Gupta V
> 
> 
> 
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