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Hi,
I am making attempts to make the output of the transformed XML to be able to display different images based on the nodes and string length. Below is the XSLT: XSLT:
<xsl:when test="$rendition!=''"> <div> <xsl:attribute name="class"> <xsl:value-of select="$rendition"/> </xsl:attribute> <xsl:if test="string-length(child::text())<'25'"> <xsl:attribute name="style"> background-image:url('<xsl:value-of select="./@rendition"/>.png') </xsl:attribute> </xsl:if> <xsl:if test="string-length('25 ' < child::text() < '50')"> <xsl:attribute name="style"> background-image:url('<xsl:value-of select="./@rendition"/>_med.png') </xsl:attribute> </xsl:if> <xsl:if test="count(child::p) > 1"> <xsl:attribute name="style"> background-image:url('<xsl:value-of select="./@rendition"/>_large.png') </xsl:attribute> </xsl:if> <p>
<xsl:call-template name="rend"/>
<xsl:apply-templates/>
</p>
</div>
</xsl:when>
<xsl:otherwise>
<!--Don't display anything-->
</xsl:otherwise>
</xsl:choose>
</p>
</div>
</xsl:template>XML: <book topic="Technology" rendition="xslt" author="Tennison, Jeni" title="Beginning XSLT"> <p>New York: Apress, 2002.</p> <p>The book serves as an introduction to XSLT based on the examples of a television program set. A resourceful book for those new to the technology.</p> </book> I want to use the code displayed above (XML) to display the file name with the name of xslt_large, and now in the HTML source it does not display that, even though the code above has two <p> tags. Can anyone please help me out? Anything is appreciated. Alice
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