Please start again at the beginning. Few people are going to try to analyze
your previous messages to work out what you mean my "as described
previously" or "the one I posted earlier".

Just give us a source document, a stylesheet, the output you are getting,
and the output you want. Please make each of them complete, but brief: don't
post fragments, and don't refer back to previous postings.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Alice Ju-Hsuan Wei [mailto:ajwei@xxxxxxxxxxx] 
> Sent: 24 September 2007 12:18
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE:  [XSL]Display Different Results Based on 
> Count ofNodeSets
> 
> Hi,
> 
>    This is what I got for the output (I am actually using 
> XSLT to transform into HTML, so the XML, as described 
> previously, was that
> input)
> 
>    The output, oddly, when I used <xsl:value of 
> select="count(title)"/> instead of position() it produced 2 
> and 1, respectively, but when the <xsl:apply-templates was 
> inserted, it generates output of
> 
>    <div><p>Tennison, Jeni.</p>
>    <p><i>Beginning XSLT</i>.</p>
>     <p><i>Begining XSLT 2.0</i>.</p></div>
> 
>      <div><p>Meyer, Eric.</p>
>      <p><i>The Zen of CSS</i>.</p>
>       </div>
> 
> When I used the one I posted earlier:
> 
> <xsl:template match="title">
>        <xsl:choose>
>            <xsl:when test="position() ='1'"/>
>            <xsl:otherwise>
>                <p>
>                    <xsl:apply-templates/>
> 
>                </p>
>            </xsl:otherwise>
>        </xsl:choose>
>    </xsl:template>
> 
> It brings back the same input. However, I wanted the one on 
> the first of the <title> to be something like:
> 
>      <div><p>Tennison, Jeni. <i>Beginning XSLT</i>.</p>
>          <p><i>Begining XSLT 2.0</i>.</p></div>
> 
>       <div><p>Meyer, Eric. <i>The Zen of CSS.</i></p></div>
> 
> 
> Is there some way I can do this?
> 
> Many thanks.
> 
> Alice