Subject: RE: Re: XSLT 2.0 multi-level grouping challenge/problem
From: cknell@xxxxxxxxxx
Date: Thu, 24 May 2007 12:20:24 -0400
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Thanks, I knew a was wandering around in some tall grass. There had to be a simpler answer. Heretofore I had only used the for-each-group construct in fairly simple problems. I hadn't used the "current-group()" function before, and that proved to be the key in clearing things up.
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Charles Knell
cknell@xxxxxxxxxx - email
-----Original Message-----
From: Andrew Welch <andrew.j.welch@xxxxxxxxx>
Sent: Thu, 24 May 2007 16:13:49 +0100
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: XSLT 2.0 multi-level grouping challenge/problem
On 5/24/07, cknell@xxxxxxxxxx <cknell@xxxxxxxxxx> wrote:
> Consider this multi-level grouping problem for XSLT 2.0.
Here you go:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<table>
<tr>
<td>State</td>
<td>City</td>
<td>Organ</td>
<td>Count</td>
</tr>
<xsl:for-each-group select="/donors/donor" group-by="state">
<xsl:sort select="current-grouping-key()"/>
<tr>
<td><xsl:value-of select="state"/></td>
<td/>
<td/>
<td/>
</tr>
<xsl:for-each-group select="current-group()" group-by="city">
<xsl:sort select="current-grouping-key()"/>
<tr>
<td/>
<td><xsl:value-of select="city"/></td>
<td/>
<td/>
</tr>
<xsl:for-each-group select="current-group()"
group-by="organ">
<xsl:sort select="current-grouping-key()"/>
<tr>
<td/>
<td/>
<td><xsl:value-of select="organ"/></td>
<td><xsl:value-of
select="count(current-group())"/></td>
</tr>
</xsl:for-each-group>
</xsl:for-each-group>
</xsl:for-each-group>
</table>
</xsl:template>
</xsl:stylesheet>
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