Re: [xsl] XPath MOD 10 calculation

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Subject: Re: XPath MOD 10 calculation
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Thu, 24 May 2007 15:01:13 +0200

Abel Braaksma wrote:


   sum(
       for $i in $x[position() mod 2 = 1] return $i * 3,
       for $i in $x[position() mod 2 = 0] return $i,
       = number(substring(., string-length(.) - 1, 1))

I must be sleepy or something. "for $i in $x[position() mod 2 = 0] return $i" is the same as " $x[position() mod 2 = 0]" of course ;) and that comma should be a right parenthesis:

  sum(
      for $i in $x[position() mod 2 = 1] return $i * 3,
      $x[position() mod 2 = 0])
      = number(substring(., string-length(.) - 1, 1))

Current Thread

Re: XPath MOD 10 calculation, (continued)
- Abel Braaksma - 24 May 2007 11:40:29 -0000
  - Abel Braaksma - 24 May 2007 11:49:02 -0000
    - Jesper Tverskov - 24 May 2007 12:17:52 -0000
    - Abel Braaksma - 24 May 2007 12:50:06 -0000
    - Abel Braaksma - 24 May 2007 13:05:09 -0000 <=
    - Jesper Tverskov - 25 May 2007 05:15:10 -0000
    - Andrew Welch - 25 May 2007 08:45:29 -0000
    - David Carlisle - 25 May 2007 09:02:08 -0000
    - Andrew Welch - 25 May 2007 09:16:48 -0000

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Re: XPath MOD 10 calculation, Abel Braaksma	Thread	Re: XPath MOD 10 calculation, Jesper Tverskov
Re: XPath MOD 10 calculation, Abel Braaksma	Date	XSLT 2.0 multi-level grouping, cknell
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