#1
<xsl:stylesheet ...>

<xsl:template match="/">
  <xsl:copy-of select="/"/>
</xsl:template>

Cheers,
Wendell

Start with a recursive copy template then match the text nodes and process the new lines, for instance replace them with spaces:

<xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="node() | @*">
    <xsl:copy>
      <xsl:apply-templates select="node() | @*"/>
    </xsl:copy>
  </xsl:template>
  <xsl:template match="text()">
    <xsl:value-of select="translate(., '&#10;',' ')"/>
  </xsl:template>
</xsl:stylesheet>

Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina - http://aboutxml.blogspot.com/
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com

Senthilkumaravelan K wrote:

Hi
I want to flatten the XML node structure to single line,
I tried indent=no and it does not work for me.
Please any suggestions.
I use the following xslt
<?xml version="1.0" encoding='UTF-8'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="no" />
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
input
<node1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</node1>
output
<node1></Item1></Item1></Item1>..</node1>
Regards,
Senthil

======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
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  Mulberry Technologies: A Consultancy Specializing in SGML and XML
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