Subject: RE: Xsl:param from PHP to html
From: "Alan Hale" <alan.hale@xxxxxxxxxxx>
Date: Sat, 14 Apr 2007 13:01:11 +0100
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Thanks David for this, and you are correct in your interpretation of
what I was trying to do.
But there is still a problem and I think it relates to my use of the
header
<html
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xsl:version='1.0'>
I don't think the parameter gets passed from PHP using this header. With
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
The parameter DOES get passed. However, my HTML is not recognised.
I know this is basic stuff, but could someone explain to me how to use
the latter header and get the html tags recognised outside of a
template?
Many thanks
Alan Hale
> -----Original Message-----
>
> This is a FAQ, $SORTBY is a global parameter so it will have
> the same value throught the run so
> <xsl:sort select = "$SORTBY"
> is sorting on an equal value, so no sort at all happens.
>
> XSL variables hold values not unevaluated expressions.
> You probably meant to select an element with name equal to
> teh string value of $SORTBY, which is
>
> <xsl:sort select = "*[name()=$SORTBY]"
>
> David
>
>
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