Define the elements as members of a substitution-group S in the schema, then
you can do 

select="/objects/object/schema-element(S)"

Or do

select="/objects/object//(list|box|group)"

Michael Kay
http://www.saxonica.com/


> -----Original Message-----
> From: tom tom [mailto:tomxsllist@xxxxxxxxxxx] 
> Sent: 21 February 2007 12:29
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Selecting a group of elements with different names
> 
> Hi all,
> 
> i need to select a group of elements whose name belongs to a 
> defined list - something along the lines of:
> 
> <xsl:for-each-group
> select="/objects/object//*[name() ='list' or name()='box' or 
> name()='group']" group-by="concat(name(), @type)">
> 
> Using XSLT 2 Can you suggest a more elegant way to list the 
> element names
> than:
> 
> name() ='list' or name()='box' or name()='group'
> 
> ?
> 
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