Subject: Re: Using xsl:sort to sort negative values
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 20 Feb 2007 22:14:09 GMT
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Can anyone tell why the code below will not work?
<xsl:sort select="data" data-type="number"/>
well, we have to guess, as you haven't shown the relevant part of your
code, but my guess is that you have
<xsl:for-each select="data">
<xsl:sort select="data" data-type="number"/>
which means that the sort key in each case is the string value of
the data child of the current data element, converted to a number,
but as there are no such elements all elements get the same sort key
(NaN in xslt1, () in xslt2) and so no sorting happens.
use
<xsl:sort select="." data-type="number"/>
as you want the value of the element itself, not of a child.
David
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