Subject: Re: transforming without outputting original namespace
From: Kamal Bhatt <kbhatt@xxxxxxxxx>
Date: Mon, 05 Feb 2007 08:23:14 +1100
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Sam Carleton wrote:
Thanks to David's help, I am now transforming xml that has a
namespace. My target is a piece of HTML, so I would prefer if the
namespace was not in the output, which it is:
<div xmlns="http://www.photoparata.com/events.xsd"
xmlns:p="urn://www.photoparata.com/events.xsd" id="titlebar"/>
How do I go about getting rid of it?
Can you run your output through a second transformation? If so, then run
the output through this XSLT (this was originally sourced from
http://cocoon.apache.org/2.1/faq/faq-xslt.html) :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="*">
<!-- remove element prefix (if any) -->
<xsl:element name="{local-name()}">
<!-- process attributes -->
<xsl:for-each select="@*">
<!-- remove attribute prefix (if any) -->
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:for-each>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
--
Kamal Bhatt
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