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Given two XML fragments
<a> <b1/> <b2/> <c/> </a> and <a> <b2/> <c/> </a> I would like to wrap <b1/><b2/> into a <b/> container, and the same should happen to <b2/> when occurring alone. The other elements can be assumed to remain unchanged. While I found quite some hints on solving grouping problems in the XSLT FAQ and in the XSL list archive, I can't figure out how to solve this wrapping task using XSLT 2.0. There is an interesting posting here: http://www.biglist.com/lists/xsl-list/archives/200201/msg00804.html But I don't know how this could serve as a basis for a solution to my problem. I suspect that "for-each-group" should be my friend; how would I need to use it here? Or is there any other, more elegant solution? Yours, Yves
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