Subject: RE: Special character as element name
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Thu, 25 Jan 2007 08:46:38 -0000
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XSLT transforms XML to XML. <#x> is not well-formed XML, so you can't
produce it using XSLT.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: San [mailto:san_sar@xxxxxxxxx]
> Sent: 25 January 2007 08:20
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Special character as element name
>
> Dear all,
>
> Many thanks for answering my questions the other day.
> Now I encounter some problem, I search for the answer but
> haven't got the right one.(using version 1.0 and
> xalan)
>
> Also This is my xml input file
>
> <Query ID="2" >
> <QueryHead URI="#x">
> </QueryHead>
> </Query>
>
> I would like to have the output (getting the attributes
> value) as the element name
>
> <Body ID="2" >
> <#x/>
> </Body>
>
> I am trying using this xslt file (below), which ok if the
> attributes value not special character (X without #)but not #x
>
> <Body>
> <xsl:element name="{//Query/@URI}"/>
> </Body>
>
> I tried several possibility, first I used the unicode for
> replacing this # with hexadecimal. stil not work, then I
> change the encoding type in the xslt file
>
> <?xml version="1.0" encoding="iso-8859-1"?>
>
> <xsl:output method="xml" indent="yes"
> encoding="ISO-8859-1"/>
>
> Stil doesn't give me result.
> I really stuck with this :(
>
> thanks a lot for your help
> san
>
>
>
>
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