Subject: RE: Numbering: position() ?
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Wed, 10 Jan 2007 10:52:17 -0000
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1. The value of position() within an xsl:template depends on the position of
the node within the set of nodes selected by the select expression of the
corresponding xsl:apply-templates, which you haven't shown us.
2. You don't say what numbering you would consider correct. If you're
looking for multi-level numbering, try <xsl:number level="multiple"/>. If
you want single-level numbering, consider <xsl:number level="any"/>.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: Sven Waibel [mailto:sven.waibel@xxxxxxxx]
> Sent: 10 January 2007 10:41
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Numbering: position() ?
>
> Hi,
>
> i got following xml:
>
> <book id="1">
> <page>
> <special>
> <page>
> <page>
> </special>
> <page>
> <page>
> </book>
>
> xslt:
>
>
> <xsl:template match="page">
> <xsl:value-of select="concat(concat(ancestor::book/$id,
> '.'), position())"/> </xsl:template>
>
> I got this numbering:
> 1.1
> 1.1
> 1.2
> 1.3
> 1.4
>
> How can i achieve that the numbering is correct?
>
> Thanks
> Sven
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